Perfect powers in an alternating sum of consecutive cubes

Article Type

Research Article

Publication Title

Glasnik Matematicki

Abstract

In this paper, we consider the problem about finding out perfect powers in an alternating sum of consecutive cubes. More precisely, we completely solve the Diophantine equation (x +1)3 −(x+2)3 +···− (x + 2d)3 + (x + 2d + 1)3 = zp, where p is prime and x,d,z are integers with 1 ≤ d ≤ 50.

First Page

37

Last Page

53

DOI

10.3336/gm.55.1.04

Publication Date

6-1-2020

Comments

Open Access, Green

This document is currently not available here.

Share

COinS